Even and Odd Functions

I almost forgot about this... Oh well... better late than never...

Ok so, from what I understand from the formulas:

f(x) -- This is what we start with.
-f(x) -- This is what we have to find.
f(-x) -- And this is what we have to get.

The graph/function is even if: f(x) = f(-x)
The graph/function is odd if: -f(x) = f(-x)
Note (for my examples)
In an even function points are across from the y-axis, in quadrants I & II
In and odd function points are diagonal from the origin, in qudrants I & III

Examples are needed maybe? Well then... for the sake of simplicity I'll use
1. f(x) = x
2. f(x) = x²

For the first equation (after some very simple calculations...):
f(x) = x
-f(x) = -x
f(-x) = -x
The latter two equation are the same causing -f(x) = f(-x)
This means that the graph is odd.

For the second equation (after equally simple calculations...):
f(x) = x²
-f(x) = x²
f(-x) = -x²
In this case, the first two equations are the same causing f(x) = f(-x)
This means that the graph is even.

Pictures too? Well then... the two graphs:

1. f(x) = x

ODD FUNCTION

Here you can see that the points have been

rotated 180 degrees from the origin

so that they lie in quadrants I & III

2. f(x) = x²
EVEN FUNCTION

In this graph the points are

directly across the y-axis

as if quadrant II is a mirror image of quadrant I